How to prepare 0.5M HCl Solution?
For HCl, the molecular mass and equivalent mass both are equal due to the availability of only one hydrogen ion.
Most HCl present in the market is around 37.5%
Molecular mass or equivalent mass is divided by the number of hydrogen ions. Due to only one hydrogen ion, the molecular mass is 36.458g/mol.
To prepare 0.5M HCl solution, either dilute from higher concentration (1M) to lower or use Concentrated HCl.
Calculation Formula:
No. of grams HCl required=(Required Conc.)x(Molecular mass)x(Required soln. in Liter)
The volume of Conc. HCl required = No. of gram HCl required/(Specific gr. x % Conc.)
As per above mentioned formula, the required volume of HCl can be calculated.
The molecular weight of HCl is 36.458 g/mol, and the specific gravity is 1.19 g/ml.
No. of gram HCl required = (0.5M) x (36.458) x (1 Lit) = 18.229
The volume of Conc. HCl required = 18.229/ (1.19 x 0.375) = 40.849 ml.
How to prepare 0.5M HCl solution:
From the above calculation 40.849 ml of 37.5% Conc. HCl is required for the preparation of 0.5M HCl solution.
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